0.2x^2-75x-1500=0

Solution for 0.2x^2-75x-1500=0 equation:

0.2x^2-75x-1500=0

a = 0.2; b = -75; c = -1500;
Δ = b2-4ac
Δ = -752-4·0.2·(-1500)
Δ = 6825
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{6825}=\sqrt{25*273}=\sqrt{25}*\sqrt{273}=5\sqrt{273}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-75)-5\sqrt{273}}{2*0.2}=\frac{75-5\sqrt{273}}{0.4}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-75)+5\sqrt{273}}{2*0.2}=\frac{75+5\sqrt{273}}{0.4}
$